-16x^2+43x+4=0

Solution for -16x^2+43x+4=0 equation:

-16x^2+43x+4=0

a = -16; b = 43; c = +4;
Δ = b2-4ac
Δ = 432-4·(-16)·4
Δ = 2105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{2105}}{2*-16}=\frac{-43-\sqrt{2105}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{2105}}{2*-16}=\frac{-43+\sqrt{2105}}{-32}
$